Question

What is the value of $\dfrac{3}{5}$ times $\dfrac{7}{9}$?

Answer 1

Hint: From the question given that we have to find the $\dfrac{3}{5}$ times $\dfrac{7}{9}$. It means we have to multiply both of them, when multiplying two fractions, the process is to multiply the numerators and then multiply the denominators. Then we can reduce the answer if possible.

Complete step-by-step solution:
From the question given we have to find the $\dfrac{3}{5}$ times $\dfrac{7}{9}$.
It means we have to multiply both of them, when multiplying two factors, the process is to multiply the numerators and then multiply the denominators.
$\Rightarrow \dfrac{3}{5}\times \dfrac{7}{9}$
First, we will multiply the numerators,
$\Rightarrow \dfrac{3}{5}\times \dfrac{7}{9}$
$\Rightarrow \dfrac{21}{5\times 9}$
Now we will multiply the denominator terms,
$\Rightarrow \dfrac{21}{45}$
Therefore, this can be reduced further both the numerator and denominator will be divided by 3.
By this will be reduced as
$\Rightarrow \dfrac{7}{15}$
Therefore, the required answer is $ \dfrac{7}{15}$

Note: Students should understand the question properly, if students divide the $\dfrac{7}{9}$ with $\dfrac{3}{5}$, instead of multiplying the whole answer will be wrong, the term in the question that what times means it implies that student should do multiplication.