Answer
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Hint: The frequency of x-rays, $\gamma $-rays and visible light waves are fixed and experimentally calculated by formula $f = \dfrac{c}{\lambda }$
Where f $ = $ frequency of wave
c $ = $ speed of light
$\lambda = $ wavelength of wave
Complete step by step solution:
X-rays are electromagnetic radiation and its wavelength experimentally given as
$a = 3 \times {10^{19}}$ to $1 \times {10^{16}}$ …..(1)
$\gamma $-rays are also the part of electromagnetic radiation & its wavelength range is given by
$b = 3 \times {10^{22}}$ to $3 \times {10^{18}}$ …..(2)
Visible light waves are also the part of electromagnetic waves & its wavelength the range is given as
$c = 8 \times {10^{14}}$ to $4 \times {10^{14}}$ …..(3)
On comparing equation (1), (2) & (3) we get
$\boxed{b > a, b > c}$
Hence option A is correct.
Note: There are many other types of radiation present in the electromagnetic wave spectrum which are infra-red radiation, microwaves, radio waves, $\gamma $-rays, x-rays, visible rays, ultra-violet etc.
Where f $ = $ frequency of wave
c $ = $ speed of light
$\lambda = $ wavelength of wave
Complete step by step solution:
X-rays are electromagnetic radiation and its wavelength experimentally given as
$a = 3 \times {10^{19}}$ to $1 \times {10^{16}}$ …..(1)
$\gamma $-rays are also the part of electromagnetic radiation & its wavelength range is given by
$b = 3 \times {10^{22}}$ to $3 \times {10^{18}}$ …..(2)
Visible light waves are also the part of electromagnetic waves & its wavelength the range is given as
$c = 8 \times {10^{14}}$ to $4 \times {10^{14}}$ …..(3)
On comparing equation (1), (2) & (3) we get
$\boxed{b > a, b > c}$
Hence option A is correct.
Note: There are many other types of radiation present in the electromagnetic wave spectrum which are infra-red radiation, microwaves, radio waves, $\gamma $-rays, x-rays, visible rays, ultra-violet etc.
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