
Number of one-one functions from A to B where n(A)= 4 and n(B)= 5.
a). 4
b). 5
c). 120
d). 90
Answer
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Hint: Type of questions is based on the function topic more precisely on the classification of Function. As there are five types of functions
i). one-one function
ii). many one function
iii). onto function
iv). into function
v). Bijective function
Complete step-by-step solution:
One –one function is also known as injective function. A one-one function is a function in which for one input we get one output. As to find one –one function we had a direct formula through which we can easily find the one-one function of ‘A’ to ‘B’.
The formula is \[^{n}{{P}_{m}}\] only if $n\ge m$
In which ‘n’ and ‘m’ are the number of elements of B and A respectively. and where p is for permutation, which is further solved as $\dfrac{n!}{(n-m)!}$
Moving further with our question where
n(A)= number of elements of A= 4= m
n(B)= number of elements of B= 5= n
So by comparing it with above formula ‘m’ = 4 and ‘n’= 5
On solving we will get
\[\begin{align}
& {{=}^{n}}{{P}_{m}} \\
& {{=}^{5}}{{P}_{4}} \\
& =\dfrac{5!}{(5-4)!} \\
& =\dfrac{5!}{1!} \\
& =\dfrac{5\times 4\times 3\times 2\times 1}{1} \\
& =120 \\
\end{align}\]
Hence, the number of one-one functions are 120. So the answer is 120, i.e. option C.
Note: while solving keep in mind that ‘n’ is the number of elements in ‘B’ and ‘m’ is the number of elements in ‘A’. Moreover this formula is only valid when n is greater than or equal to m $n\ge m$ . If it comes out to be less than m than the answer would be zero (0).
i). one-one function
ii). many one function
iii). onto function
iv). into function
v). Bijective function
Complete step-by-step solution:
One –one function is also known as injective function. A one-one function is a function in which for one input we get one output. As to find one –one function we had a direct formula through which we can easily find the one-one function of ‘A’ to ‘B’.
The formula is \[^{n}{{P}_{m}}\] only if $n\ge m$
In which ‘n’ and ‘m’ are the number of elements of B and A respectively. and where p is for permutation, which is further solved as $\dfrac{n!}{(n-m)!}$
Moving further with our question where
n(A)= number of elements of A= 4= m
n(B)= number of elements of B= 5= n
So by comparing it with above formula ‘m’ = 4 and ‘n’= 5
On solving we will get
\[\begin{align}
& {{=}^{n}}{{P}_{m}} \\
& {{=}^{5}}{{P}_{4}} \\
& =\dfrac{5!}{(5-4)!} \\
& =\dfrac{5!}{1!} \\
& =\dfrac{5\times 4\times 3\times 2\times 1}{1} \\
& =120 \\
\end{align}\]
Hence, the number of one-one functions are 120. So the answer is 120, i.e. option C.
Note: while solving keep in mind that ‘n’ is the number of elements in ‘B’ and ‘m’ is the number of elements in ‘A’. Moreover this formula is only valid when n is greater than or equal to m $n\ge m$ . If it comes out to be less than m than the answer would be zero (0).
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