Answer
Verified
465k+ views
Hint
Magnification can be defined with the height of the image as well as the distance of the object. It is the ratio between height of object and height of image. It is denoted by “m” in the mathematical formula.
Complete Step By Step Solution
Let’s begin with what is Magnification. It is described as the ratio of a height of as Image to height of an object which means size of image to size of object. We can also term it as the distance of an image from the lens to the distance of an object from the lens.
So. In a formatted way. It can be written as
Magnification (m) $ = \dfrac{{{\text{Size}}\;{\text{of}}\;{\text{the}}\;{\text{Image}}}}{{{\text{Size}}\;{\text{of}}\;{\text{the}}\;{\text{object}}}}$
$ \Rightarrow m = \dfrac{{{h_2}}}{{{h_1}}}$
Or we use distance then-
$ \Rightarrow \;{\text{magnification}}\;{\text{(m)}}\;{\text{ = }}\;\dfrac{{{\text{Image}}\;{\text{distance}}}}{{{\text{object}}\;{\text{distance}}}}$
$ \Rightarrow m = \dfrac{v}{u}$
Where, $v$ − Ιmage distance from the lens,
$u$ − object distance from the lens.
Note
The Value of Magnification describes the Property of Image. Where $\left| m \right| > 1$ means enlarged and $\left| m \right| < 1$ means smaller than the object. The sign denotes the property of the same side or on the opposite side of the lens.
Magnification can be defined with the height of the image as well as the distance of the object. It is the ratio between height of object and height of image. It is denoted by “m” in the mathematical formula.
Complete Step By Step Solution
Let’s begin with what is Magnification. It is described as the ratio of a height of as Image to height of an object which means size of image to size of object. We can also term it as the distance of an image from the lens to the distance of an object from the lens.
So. In a formatted way. It can be written as
Magnification (m) $ = \dfrac{{{\text{Size}}\;{\text{of}}\;{\text{the}}\;{\text{Image}}}}{{{\text{Size}}\;{\text{of}}\;{\text{the}}\;{\text{object}}}}$
$ \Rightarrow m = \dfrac{{{h_2}}}{{{h_1}}}$
Or we use distance then-
$ \Rightarrow \;{\text{magnification}}\;{\text{(m)}}\;{\text{ = }}\;\dfrac{{{\text{Image}}\;{\text{distance}}}}{{{\text{object}}\;{\text{distance}}}}$
$ \Rightarrow m = \dfrac{v}{u}$
Where, $v$ − Ιmage distance from the lens,
$u$ − object distance from the lens.
Note
The Value of Magnification describes the Property of Image. Where $\left| m \right| > 1$ means enlarged and $\left| m \right| < 1$ means smaller than the object. The sign denotes the property of the same side or on the opposite side of the lens.
Recently Updated Pages
Write the IUPAC name of the given compound class 11 chemistry CBSE
Write the IUPAC name of the given compound class 11 chemistry CBSE
Write the IUPAC name of the given compound class 11 chemistry CBSE
Write the IUPAC name of the given compound class 11 chemistry CBSE
Write the IUPAC name of the given compound class 11 chemistry CBSE
Write the IUPAC name of the given compound class 11 chemistry CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
Which are the Top 10 Largest Countries of the World?
Which is the longest day and shortest night in the class 11 sst CBSE
What is the definite integral of zero a constant b class 12 maths CBSE
Name five important trees found in the tropical evergreen class 10 social studies CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE