
How do you solve $$2x + 5 = - 2$$?
Answer
400.8k+ views
Hint: Here in this question, we have to solve the given equation and it is in the form of an algebraic equation having a variable x. Solving this equation, we have to find the unknown value x by using the basic arithmetic operation like multiplication and division.
Complete step by step answer:
The given equation is an algebraic equation. The algebraic equation is a combination of variable and constant and which has an equal sign. So we use arithmetic operations and solve it further.
Now consider the given equation
$$ \Rightarrow \,\,2x + 5 = - 2$$
Subtract 5 from both sides of the equation.
$$ \Rightarrow \,\,2x = - 2 - 5$$
On simplification, we get
$$ \Rightarrow \,\,2x = - 7$$
Now divide the above equation both side by 2, then we get
$$\therefore \,\,\,\,x = - \dfrac{7}{2}$$
Hence, it’s a required solution.
We can also verify the given question by substituting the value of x.
Consider $$2x + 5 = - 2$$. Substitute the value of x as $$ - \dfrac{7}{2}$$, so we have
$$ \Rightarrow \,\,2\left( { - \dfrac{7}{2}} \right) + 5 = - 2$$
On simplification we get
$$ \Rightarrow \,\, - 7 + 5 = - 2$$
$$\therefore \,\,\, - 2 = - 2$$
Hence LHS is equal to RHS.
Note: There are three methods to solve linear equations in one variable:
1. Trial and error
2. Inverse Operations
3. Transposition method
If the algebraic expression contains only one unknown, we determine the value by using simple arithmetic operations.
Complete step by step answer:
The given equation is an algebraic equation. The algebraic equation is a combination of variable and constant and which has an equal sign. So we use arithmetic operations and solve it further.
Now consider the given equation
$$ \Rightarrow \,\,2x + 5 = - 2$$
Subtract 5 from both sides of the equation.
$$ \Rightarrow \,\,2x = - 2 - 5$$
On simplification, we get
$$ \Rightarrow \,\,2x = - 7$$
Now divide the above equation both side by 2, then we get
$$\therefore \,\,\,\,x = - \dfrac{7}{2}$$
Hence, it’s a required solution.
We can also verify the given question by substituting the value of x.
Consider $$2x + 5 = - 2$$. Substitute the value of x as $$ - \dfrac{7}{2}$$, so we have
$$ \Rightarrow \,\,2\left( { - \dfrac{7}{2}} \right) + 5 = - 2$$
On simplification we get
$$ \Rightarrow \,\, - 7 + 5 = - 2$$
$$\therefore \,\,\, - 2 = - 2$$
Hence LHS is equal to RHS.
Note: There are three methods to solve linear equations in one variable:
1. Trial and error
2. Inverse Operations
3. Transposition method
If the algebraic expression contains only one unknown, we determine the value by using simple arithmetic operations.
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