
How do you find the median of 4 numbers?
Answer
523.5k+ views
Hint: There are two cases in finding the median one is when there are an odd number of values and second is when there is an even number of values. As we have to find the median of four numbers it means we have an even number of values. In this case we add two middle numbers and divide the sum by 2.
Complete step by step solution:
We have to explain how we can find the median of 4 numbers.
We know that median is the central element of a group of numbers arranged in the proper sequence according to their size. To find the median first we have to arrange the data according to their size. If we have an odd number of terms then the middle term is the median. If we have an even number of terms then we have to add two middle terms and then divide the sum by 2. The mean we get is the median.
Let us assume 4 numbers as 24,89,31,12
Let us arrange the numbers in ascending order then we will get
$\Rightarrow 12,24,31,89$
Now, as we have an even number of terms let us add two middle terms and divide the sum by 2. Then we will get
$\begin{align}
& \Rightarrow \dfrac{24+31}{2} \\
& \Rightarrow \dfrac{55}{2} \\
& \Rightarrow 27.5 \\
\end{align}$
Hence $27.5$ is the median.
Note:
Data is categorized into two types one is grouped data and second is ungrouped data. Above discussed procedure is for ungrouped data. For grouped data we will use the frequency distribution. First we need to calculate the cumulative frequency then we will use the following formula to calculate median:
$Median=l+\left( \dfrac{h}{f} \right)\left( \dfrac{n}{2}-c \right)$
Where, l = lower class interval
h = class interval size
f = median class’s frequency
n = total frequency
c = cumulative frequency of preceding class.
Complete step by step solution:
We have to explain how we can find the median of 4 numbers.
We know that median is the central element of a group of numbers arranged in the proper sequence according to their size. To find the median first we have to arrange the data according to their size. If we have an odd number of terms then the middle term is the median. If we have an even number of terms then we have to add two middle terms and then divide the sum by 2. The mean we get is the median.
Let us assume 4 numbers as 24,89,31,12
Let us arrange the numbers in ascending order then we will get
$\Rightarrow 12,24,31,89$
Now, as we have an even number of terms let us add two middle terms and divide the sum by 2. Then we will get
$\begin{align}
& \Rightarrow \dfrac{24+31}{2} \\
& \Rightarrow \dfrac{55}{2} \\
& \Rightarrow 27.5 \\
\end{align}$
Hence $27.5$ is the median.
Note:
Data is categorized into two types one is grouped data and second is ungrouped data. Above discussed procedure is for ungrouped data. For grouped data we will use the frequency distribution. First we need to calculate the cumulative frequency then we will use the following formula to calculate median:
$Median=l+\left( \dfrac{h}{f} \right)\left( \dfrac{n}{2}-c \right)$
Where, l = lower class interval
h = class interval size
f = median class’s frequency
n = total frequency
c = cumulative frequency of preceding class.
Recently Updated Pages
The height of a solid metal cylinder is 20cm Its r-class-10-maths-ICSE

If a train crossed a pole at a speed of 60kmhr in 30 class 10 physics CBSE

Name the Writs that the High Courts are empowered to class 10 social science CBSE

A tower is 5sqrt 3 meter high Find the angle of el-class-10-maths-CBSE

Immediate cause of variations of A Mutations B Environmental class 10 biology CBSE

A rectangular container whose base is a square of side class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Tropical deciduous trees shed their leaves in the dry class 10 social science CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Write a letter to the principal requesting him to grant class 10 english CBSE

The uses of bleaching powder are A It is used bleaching class 10 chemistry CBSE

Leap year has days A 365 B 366 C 367 D 368 class 10 maths CBSE

