Answer
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Hint: Resistance is defined as the property of the conductor which opposes the flow of electric current. It is also defined as the ratio of the voltage applied to the electric current flowing through it.Resistivity is defined as the resistance offered by the material per unit length for unit cross-section. The SI unit of resistivity is Ohm.meter.
Complete step by step answer:
(a) Relation between resistance and electrical resistance within the form of cylinder of length $l$ and area of cross section $A$,
Then we get the formula,
$R = \dfrac{{\rho l}}{A}$
Where $R$ is resistance.
Now, $\rho = \dfrac{{AR}}{l} \to \left( 1 \right)$
currently substitute the units of $R, A$, and $l$, we get
where as, $R=\Omega $
$A={m^2}$ and $l=m$ then
$\Rightarrow \rho = \dfrac{{\Omega \times {m^2}}}{m} \\
\Rightarrow \rho = \Omega m \\ $
$\therefore \rho = \Omega - m$
(b) only if, resistance, R=$100\Omega $, Length $l=5\,m$ and area of cross section $A= 3 \times {10^{ - 7}}\,{m^2}$.
Now we will calculate the resistivity in metal by equation $\rho = \dfrac{{AR}}{l} \to (1)$
Substitute the particularly values with in the equation (1), then we tend to go
$\rho = \dfrac{{100 \times 3 \times {{10}^{ - 7}}}}{5}$
$\Rightarrow \rho = 0.000006\Omega - m \\
\therefore \rho = 6 \times {10^{ - 6}}\Omega - m \\$
Hence the resistivity of a metal is $6 \times {10^{ - 6}}\,\Omega - m$.
Note: Resistance physical phenomenon and related with synchrotron radiation that studies within the atomic layers of carbon. Property of an electric circuit system is ordinarily handling a lot of data apart from any channel in resistance. Hence the resistivity of a metal is $6 \times {10^{ - 6}}\Omega - m$.
Complete step by step answer:
(a) Relation between resistance and electrical resistance within the form of cylinder of length $l$ and area of cross section $A$,
Then we get the formula,
$R = \dfrac{{\rho l}}{A}$
Where $R$ is resistance.
Now, $\rho = \dfrac{{AR}}{l} \to \left( 1 \right)$
currently substitute the units of $R, A$, and $l$, we get
where as, $R=\Omega $
$A={m^2}$ and $l=m$ then
$\Rightarrow \rho = \dfrac{{\Omega \times {m^2}}}{m} \\
\Rightarrow \rho = \Omega m \\ $
$\therefore \rho = \Omega - m$
(b) only if, resistance, R=$100\Omega $, Length $l=5\,m$ and area of cross section $A= 3 \times {10^{ - 7}}\,{m^2}$.
Now we will calculate the resistivity in metal by equation $\rho = \dfrac{{AR}}{l} \to (1)$
Substitute the particularly values with in the equation (1), then we tend to go
$\rho = \dfrac{{100 \times 3 \times {{10}^{ - 7}}}}{5}$
$\Rightarrow \rho = 0.000006\Omega - m \\
\therefore \rho = 6 \times {10^{ - 6}}\Omega - m \\$
Hence the resistivity of a metal is $6 \times {10^{ - 6}}\,\Omega - m$.
Note: Resistance physical phenomenon and related with synchrotron radiation that studies within the atomic layers of carbon. Property of an electric circuit system is ordinarily handling a lot of data apart from any channel in resistance. Hence the resistivity of a metal is $6 \times {10^{ - 6}}\Omega - m$.
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