Answer
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Hint: The radius of a mirror is its focal length. For concave mirror focal length is considered to be negative. The two lenses are separated by a distance of 15cm and the object is placed just at the middle point which divides the distance between two lenses equally.
Complete answer:
Here ‘O’ is the object, and it is placed halfway between the two mirrors.
We know that for, concave mirror
u$_{1}$ =−7.5 and f$_{1}$ =−5
On applying mirror formulae,
$\dfrac{1}{f{{~}_{1}}}=\dfrac{1}{{{v}_{1}}}+\dfrac{1}{{{u}_{1}}}$
$\implies \dfrac{1}{{{v}_{1}}}-\dfrac{2}{15}=\dfrac{-1}{5}$
v$_{1}$=−15
From the value of v ,we can depict that the image is formed at pole of convex mirror
Now , for the convex mirror ,
u$_{2}$ =0 and f$_{2}$=+5
On applying mirror formulae,
$\implies \dfrac{1}{{{f}_{2}}}=\dfrac{1}{{{v}_{2}}}+\dfrac{1}{{{u}_{2}}}$
$\implies \dfrac{1}{{{v}_{2}}}+\dfrac{1}{0}=\dfrac{1}{5}$
$\implies v_{2}=0$
So the final image is formed at the pole of the convex mirror .
So, the correct answer is “Option A”.
Additional Information:
Snell's law is a formula that is used to describe the relation between the angle of incidence and the angle of refraction, it is referred to light or other waves passing through a boundary between two different mediums.
Angle of incidence is an angle between a ray incident on a surface and the normal.
Angle of refraction is an angle between a refracted ray on a surface and the normal.
Note:
Focal length of a convex mirror is considered as positive whereas of a concave mirror is considered negative, in the mirror formulae f is the focal length v is image distance and u is the object distance from the lens. Students sometimes confuse between object distance and image distance.
Complete answer:
Here ‘O’ is the object, and it is placed halfway between the two mirrors.
We know that for, concave mirror
u$_{1}$ =−7.5 and f$_{1}$ =−5
On applying mirror formulae,
$\dfrac{1}{f{{~}_{1}}}=\dfrac{1}{{{v}_{1}}}+\dfrac{1}{{{u}_{1}}}$
$\implies \dfrac{1}{{{v}_{1}}}-\dfrac{2}{15}=\dfrac{-1}{5}$
v$_{1}$=−15
From the value of v ,we can depict that the image is formed at pole of convex mirror
Now , for the convex mirror ,
u$_{2}$ =0 and f$_{2}$=+5
On applying mirror formulae,
$\implies \dfrac{1}{{{f}_{2}}}=\dfrac{1}{{{v}_{2}}}+\dfrac{1}{{{u}_{2}}}$
$\implies \dfrac{1}{{{v}_{2}}}+\dfrac{1}{0}=\dfrac{1}{5}$
$\implies v_{2}=0$
So the final image is formed at the pole of the convex mirror .
So, the correct answer is “Option A”.
Additional Information:
Snell's law is a formula that is used to describe the relation between the angle of incidence and the angle of refraction, it is referred to light or other waves passing through a boundary between two different mediums.
Angle of incidence is an angle between a ray incident on a surface and the normal.
Angle of refraction is an angle between a refracted ray on a surface and the normal.
Note:
Focal length of a convex mirror is considered as positive whereas of a concave mirror is considered negative, in the mirror formulae f is the focal length v is image distance and u is the object distance from the lens. Students sometimes confuse between object distance and image distance.
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