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Understanding Problems on Divisibility Rules

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How to Solve Divisibility Rule Problems with Examples

Do you know how to quickly answer whether a number is divisible by another number, just by looking at it? Yes, using divisibility rules, one can quickly answer whether a number is divisible by another number or not. The below article covers the topic of divisibility rules, deeply by discussing some divisibility rules practice problems. Reading this article, students will be able to easily find the divisors of a given number. Let us now start learning about this topic in detail in this article.


What do You Mean by Divisibility Rules?

The divisibility rules were outlined by the famous mathematician Martin Gardner in the year 1962. These serve as a convenient shorthand for checking if an integer is divisible by a given set of divisors without actually dividing, typically by looking at the digits of the number.


Divisibility Rules for the Numbers 2 to 10

  1. The Divisibility Rule for 2: Check whether the last digit of a given number is zero or even number. If yes, then the given number is divisible by 2.

  2. The Divisibility Rule for 3: Check whether the sum of the digits of a given number is divisible by 3 or not. If so, then the given number is divisible by 3.

  3. The Divisibility Rule for 4: Check whether the last two digits of a given number are divisible by 4 or not. If yes, then the given number is divisible by 4.

  4. The Divisibility Rule for 5: If the last digits of a number are 0 or 5, then the number is divisible by 5, otherwise not.

  5. The Divisibility Rule for 6: Check whether the given number is divisible by 2 and 3 both or not. If yes, then the given number is divisible by 6.

  6. The Divisibility Rule for 7: To check whether the given number is divisible by 7, one must multiply the last digit by 2, and then subtract the product from the number being left. Finally, if the difference obtained is 0 or a multiple of 7, then the given number is divisible by 7.

  7. The Divisibility Rule for 8: Check whether the last three digits of the given number are divisible by 8 or not. If yes, then the given number is divisible by 8.

  8. The Divisibility Rule for 9: Check whether the sum of the digits of a given number is divisible by 9 or not. If yes, then the given number is divisible by 9.

  9. The Divisibility Rule for 10: If the last digit of a number is zero, then the given number is divisible by 10, otherwise not.


Divisibility Rules


Divisibility Rules


Solved Problems on Divisibility Rules

1. Find whether 492 is divisible by 3 or not.

Ans: Steps to be followed to solve the divisibility problem are given:

  • Write down the original number, 492.

  • Add the individual digit of the number, 492, i.e., 4 + 9 + 2 = 15.

  • Check whether 15 is divisible by 3 or not. If yes, then the given number is divisible by 3 otherwise not.

  • As 15 is divisible by 3, we can conclude that the number is divisible by 3.

Hence, the given number 492 is divisible by 3.


Problems on Divisibility Rules


Problems on Divisibility Rules


2. Check whether 6 divides 264 or not.

Ans: Steps to be followed to solve the divisibility problem are given:

  • Write down the original number 264.

  • Now, find the prime factors of 6, i.e., 2 and 3.

  • To check whether the given number is divisible by 6 or not, one must check its divisibility with both 2 and 3.

  • As the last digit of the number 264 is even, so it is divisible by 2.

  • Now, add the individual digit of the number, 264, i.e., 2 + 6 + 4 = 12. As 12 is divisible by 3, so 264 is divisible by 3.

  • The provided number is divisible by both 2 and 3, so it is divisible by 6.

Hence, the given number, 264, is divisible by 6.


Problems on Divisibility Rules


Problems on Divisibility Rules


3. Check whether 7 divides 231 or not.

Ans: Steps to be followed to solve the divisibility problem are given below:

  • Multiply the last digit of the number 231 by 2, i.e., 1×2.

  • Now subtract the product, 2 from the number being left, i.e., 23.

  • The difference obtained is 21 which is a multiple of 7.

Thus, the given number, 231, is divisible by 7.


Divisibility Rule Practice Problems

Some of the divisibility rule practice problems are given below, which need to be solved by the students themselves.


1. Check the divisibility of 4 for the number 864.

Ans: The given number is divisible by 4.


2. Does 5 divide the number 46825 leaving no remainder?

Ans. Yes.


3. Without actual division, find whether 35278 is divisible by 6 or not.

Ans: No.


4. Explain the divisibility rule of 7.


Aptitude Questions on Divisibility

1. Is 414 divisible by 6? Check using the divisibility rule of 6.

Ans: Yes.


2. How many of the following numbers are divisible by 132?

264, 396, 462, 792, 968, 2178, 5184, 6336

Ans: Only four numbers are divisible by 132, i.e., 264, 396, 792, and 6336.


3. Is 399 divisible by 7?

Ans: Yes.


Summary

These rules serve as the most important tool in Mathematics to solve any problem involving division. Every topic in this article has been discussed to the point in a simple language and attractive style for better clarity of the concepts. Some Aptitude Questions on Divisibility are also given along with their answers to make students aware of the pattern.

FAQs on Understanding Problems on Divisibility Rules

1. What are divisibility rules in maths?

Divisibility rules are short mathematical tests used to determine whether one number is exactly divisible by another without performing full division. These rules help check divisibility quickly using digits of the number.

  • They are commonly used for numbers like 2, 3, 4, 5, 6, 8, 9, 10, 11.
  • If a number follows the rule, the remainder is 0.
  • They simplify calculations in factors, multiples, and prime factorization.

2. What is the divisibility rule for 2?

A number is divisible by 2 if its last digit is 0, 2, 4, 6, or 8. This means the number must be even.

  • Example: 246 → last digit is 6 → divisible by 2.
  • Example: 135 → last digit is 5 → not divisible by 2.
This rule works because even numbers are multiples of 2.

3. What is the divisibility rule for 3?

A number is divisible by 3 if the sum of its digits is divisible by 3. Add all digits and check the result.

  • Example: 123 → 1+2+3 = 6 → divisible by 3 → so 123 is divisible by 3.
  • Example: 124 → 1+2+4 = 7 → not divisible by 3.
This rule is commonly used in factor and multiple problems.

4. What is the divisibility rule for 4?

A number is divisible by 4 if its last two digits form a number divisible by 4. Only the last two digits matter.

  • Example: 316 → last two digits are 16 → 16 ÷ 4 = 4 → divisible.
  • Example: 318 → last two digits are 18 → not divisible by 4.
This rule works because 100 is divisible by 4.

5. What is the divisibility rule for 5?

A number is divisible by 5 if its last digit is 0 or 5. This rule is easy to apply by checking only the unit place.

  • Example: 250 → ends in 0 → divisible by 5.
  • Example: 375 → ends in 5 → divisible by 5.
  • Example: 372 → ends in 2 → not divisible by 5.

6. What is the divisibility rule for 6?

A number is divisible by 6 if it is divisible by both 2 and 3. It must satisfy both rules together.

  • Step 1: Check if the number is even (divisible by 2).
  • Step 2: Check if the sum of digits is divisible by 3.
  • Example: 246 → even and 2+4+6=12 (divisible by 3) → divisible by 6.

7. What is the divisibility rule for 8?

A number is divisible by 8 if its last three digits form a number divisible by 8. Only the last three digits need to be checked.

  • Example: 1,024 → last three digits are 024 (24) → divisible by 8.
  • Example: 1,026 → last three digits are 026 (26) → not divisible by 8.
This works because 1000 is divisible by 8.

8. What is the divisibility rule for 9?

A number is divisible by 9 if the sum of its digits is divisible by 9. This rule is similar to the rule for 3.

  • Example: 729 → 7+2+9 = 18 → 18 ÷ 9 = 2 → divisible.
  • Example: 738 → 7+3+8 = 18 → divisible by 9.
This rule is frequently used in checking calculations.

9. What is the divisibility rule for 11?

A number is divisible by 11 if the difference between the sum of alternate digits is 0 or a multiple of 11. Follow these steps:

  • Add digits in odd positions.
  • Add digits in even positions.
  • Find the difference between the two sums.
  • If the result is 0 or divisible by 11, the number is divisible by 11.
  • Example: 121 → (1+1) − 2 = 0 → divisible by 11.

10. How do you solve problems using divisibility rules?

To solve problems on divisibility rules, apply the specific rule for the given divisor and check whether the condition is satisfied. Follow these steps:

  • Step 1: Identify the divisor (such as 3, 4, 6, 9).
  • Step 2: Apply its divisibility test (digit sum, last digit, last two digits, etc.).
  • Step 3: Conclude whether the remainder is 0.
  • Example: Is 540 divisible by 9? → 5+4+0=9 → divisible → so 540 is divisible by 9.
These shortcuts help in exams, factorization, and number system problems.