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Nth Term of a Geometric Progression Explained

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How to Find the Nth Term of a GP Using the Formula with Examples

Calculating the nth term of a GP (Geometric Progression) is crucial for many school exams and competitive tests. It helps students solve problems quickly without writing out long sequences. Mastering this saves time and boosts confidence, especially when tackling sums and sequences in maths.


Formula Used in nth term of a GP

The standard formula is: \( a_n = a \times r^{n-1} \), where “a” is the first term, “r” is the common ratio, and “n” is the term position.


Here’s a helpful table to understand nth term of a GP more clearly:


nth term of a GP Table

Term Position (n)Formula UsedSample Value
1 (First) a × r0 a
2 (Second) a × r1 a × r
3 (Third) a × r2 a × r²
n (Any Term) a × rn-1 Depends on n, a, r

This table shows how the formula for the nth term of a GP applies to any position in the sequence, simply by changing the value of n.


What is a Geometric Progression?

A geometric progression (GP) is a number sequence where each term is found by multiplying the previous term by a common ratio (r). For example, in the sequence 2, 4, 8, 16, ... each term is multiplied by 2 to get the next. The GP formula allows you to directly calculate any term in the sequence without listing all previous terms. To learn more about sequences and related ideas, see sequences and series.


Worked Example – Solving a Problem

1. Write down the problem: Find the 5th term of a GP where the first term (a) is 3 and the common ratio (r) is 2.

2. Use the formula: \( a_n = a \times r^{n-1} \)
Plug in values: \( a_5 = 3 \times 2^{5-1} \)

3. Calculate the exponent: \( 2^{5-1} = 2^{4} = 16 \)
So \( a_5 = 3 \times 16 \)

4. Perform the multiplication: \( 3 \times 16 = 48 \)
Final answer: 48


You can practice more problems or explore the arithmetic-geometric sequence for advanced cases.


Practice Problems

  • Find the 7th term of a GP where a = 2 and r = 3.
  • In the GP 5, 10, 20, ..., what is the 6th term?
  • If the fifth term of a GP is 81 and its first term is 3, with r > 0, find r.
  • Which term of the GP 1, 4, 16, ... is 1024?

Common Mistakes to Avoid

  • Confusing nth term of a GP with the arithmetic progression (AP) nth term formula (AP uses addition, GP uses multiplication).
  • Forgetting that the power in r should always be (n-1), not n.
  • Mixing up the order of the sequence (using wrong values for n).
  • Using the wrong common ratio (r) by not checking two consecutive terms for multiplication.

Real-World Applications

The concept of nth term of a GP is used in many practical fields, such as calculating compound interest in banking, analyzing population growth, and studying patterns in investments or energy usage. Understanding geometric progressions helps connect these maths concepts to real-world situations that Vedantu explains clearly for students.


We explored the idea of nth term of a GP, its formula, detailed steps to solve related problems, and its importance in real-world settings. Review the formula and keep practicing with Vedantu for exam-ready confidence in sequences and series.


To further deepen your understanding or to tackle competitive exam questions, visit these helpful resources: sum of GP and arithmetic progression for comparisons, and nth term of an AP for AP term calculations.

FAQs on Nth Term of a Geometric Progression Explained

1. What is the nth term of a GP?

The nth term of a GP (Geometric Progression) is given by the formula aₙ = a × rⁿ⁻¹, where a is the first term and r is the common ratio.

  • a = first term
  • r = common ratio
  • n = term number
This formula helps calculate any specific term without listing all previous terms in the geometric sequence.

2. What is the formula for the nth term of a geometric progression?

The formula for the nth term of a geometric progression is aₙ = a × rⁿ⁻¹.

  • Multiply the first term (a) by the common ratio (r).
  • Raise r to the power of (n − 1).
This formula is used to find any term in a GP quickly and accurately.

3. How do you find the nth term of a GP?

To find the nth term of a GP, use the formula aₙ = a × rⁿ⁻¹ and substitute the given values.

  • Step 1: Identify the first term (a).
  • Step 2: Find the common ratio (r = second term ÷ first term).
  • Step 3: Substitute n into the formula.
Example: In 3, 6, 12, 24…, a = 3 and r = 2. The 5th term is 3 × 2⁴ = 48.

4. What is the common ratio in a GP?

The common ratio (r) in a GP is the number by which each term is multiplied to get the next term.

  • Formula: r = second term ÷ first term
  • If r > 1, the GP increases.
  • If 0 < r < 1, the GP decreases.
For example, in 5, 15, 45…, r = 15 ÷ 5 = 3.

5. Can you give an example of finding the nth term of a GP?

Yes, the nth term is found using aₙ = a × rⁿ⁻¹ with the given values.

  • Example GP: 2, 6, 18, 54…
  • a = 2, r = 3
  • Find the 4th term: a₄ = 2 × 3³
  • a₄ = 2 × 27 = 54
This confirms the correctness of the geometric progression formula.

6. What is the difference between arithmetic progression and geometric progression?

The main difference is that an AP adds a constant difference, while a GP multiplies by a constant ratio.

  • AP nth term: aₙ = a + (n − 1)d
  • GP nth term: aₙ = a × rⁿ⁻¹
  • AP example: 2, 5, 8, 11 (difference = 3)
  • GP example: 2, 6, 18, 54 (ratio = 3)
This distinction is important when identifying sequence types.

7. What happens to the nth term when the common ratio is less than 1?

If the common ratio r is between 0 and 1, the nth term decreases as n increases.

  • Formula remains: aₙ = a × rⁿ⁻¹
  • Powers of r become smaller.
Example: In 8, 4, 2, 1…, r = 1/2, so terms keep getting smaller and approach zero.

8. How do you find the first term if the nth term and common ratio are given?

The first term is found using a = aₙ ÷ rⁿ⁻¹ when the nth term and r are known.

  • Start from: aₙ = a × rⁿ⁻¹
  • Rearrange: a = aₙ / rⁿ⁻¹
Example: If a₅ = 162 and r = 3, then a = 162 ÷ 3⁴ = 162 ÷ 81 = 2.

9. How do you know if a sequence is a GP?

A sequence is a geometric progression if the ratio between consecutive terms is constant.

  • Check: term₂ ÷ term₁
  • Check: term₃ ÷ term₂
  • If ratios are equal, it is a GP.
Example: In 4, 12, 36…, 12 ÷ 4 = 3 and 36 ÷ 12 = 3, so it is a GP with r = 3.

10. Why is the nth term formula of a GP a × rⁿ⁻¹?

The formula aₙ = a × rⁿ⁻¹ works because each term is obtained by multiplying the previous term by r repeatedly.

  • 1st term: a
  • 2nd term: a × r
  • 3rd term: a × r × r = a × r²
  • nth term: a × rⁿ⁻¹
The exponent (n − 1) counts how many times the common ratio is multiplied.