

Just like in geometry we study about shapes, in algebra, we study about arithmetic operations. Similarly, calculus is about continuous change. Calculus is divided into two parts called: (i) differential calculus (ii) integral calculus
Differential calculus is also known by the names, differentiation and derivative.
Integral calculus is also known by the names, integration and antiderivative. So what is Differentiation? Differentiation is the study of the rate of change in quantities. Geometrically speaking, when we find the derivative of a point on a curve it is the slope of the tangent line. To find the derivative of a function it’s necessary that a derivative exists and is defined at the point
For example:
F(x)= x²+x-2=0
F’(x)= 2x+1.
Application of Differentiation:
Differentiation is used in the following:
a) For optimization
b) Physics
c) Differential Equations
d) Mean Value Theorem
The reverse process of differentiation is integration.
Integration:
Integration is a mathematical concept wherein you join and put things back together. Geometrically speaking, integration is a process to find the area under the curve. It is represented in the following way:
∫f(x) dx
where ∫ is a symbol for integration, f(x) is the integrand and ‘x’ is the integration variable.
Integration can be done of two type integrals namely,
(i) Definite Integrals
(ii) Indefinite Integrals
Definite integrals are those integrals which have a start and an end value. This means that the curve that’s being discussed is within an interval [a, b].
Indefinite Integrals are those integrals which do not have a start and an end value.
For example:
∫2x + 1 dx
=x²+x+c, where c is a constant function.
There are various ways of integrating a function. These ways are:
a) Integration by Substitution
b) Integration by Parts
c) Integration of Trigonometric Functions
d) Integration of Some Particular Function
e) Integration by Partial Fraction
We will talk about every method of integration in detail.
Integration by Substitution
There are times when the given function is a little complicated and thus, making it difficult for us to integrate. To make it easy we use a different independent variable to make it easier to integrate. This is known integration by substitution.
∫sin(1-x)(2-cos(1-x)) dx
u = 2 - cos(1 - x) du = -sin(1 - x)dx ⇒sin(1 - x)dx = -du
∫sin(1-x)(2-cos(1-x)) dx = -∫u du
= - ⅕ u + c
Integration by Parts
Integration by parts requires the integrand function to be the multiple of two more functions.
Let’s say we have an integrand function to be f(x).g(x).
Integration by parts is represented as:
∫f(x).g(x).dx = f(x).∫g(x).dx–∫(f′(x).∫g(x).dx).dx
A rule is followed while integrating functions by the method of integration by parts. It’s called ILATE. It stands for inverse trigonometry, logarithm, algebra, trigonometry and exponents.
Integration of Trigonometric Functions
While integrating a function, if trigonometric functions are present in the integrand we can use trigonometric identities to simplify the function to make it simpler for integration. Some integration formulae of trigonometric functions are given below:
Sin2x= \[\frac{1-cos2x}{2}\]
cos2x= \[\frac{1+cos2x}{2}\]
4sin3x=3sinx–sin3x
4cos3x=3cosx+cos3x
Mentioning integration of all trigonometric functions will be very difficult since there are many formulae.
Integration of Some Particular Function
Some functions when being integrated involve the usage of essential formulae of integration. It is applied to our given function to have it in a standard form of the integrand.
Integration by Partial Fraction
Integrals can also be represented in p/q form, the way rational numbers are expressed. By expressing integrals in this way we can use some special formulae to easily integrate the given function.
Definite Integrals
The major purpose of integration is to find the area under the curve. You can find the area of definite integrals only. Other than using integration, there’s another to find the area which is called Limit of Sums.
The formula for limit of sum is:
\[\int_{a}^{b}\] f(x) dx = (b - a) \[\lim_{n\rightarrow∞ }\] (1/n)[f(a) + f(a + h) + … + f(a + {n - 1}h)]
Definite Integrals have several properties which are used while integrating. They are discussed below:
1. \[\int_{a}^{b}\] f(x) dx = \[\int_{a}^{b}\] f(t) d(t)
2. \[\int_{a}^{b}\] f(x) dx = -\[\int_{a}^{b}\] f(x) dx
3. \[\int_{a}^{a}\] f(x) dx = 0
4. \[\int_{a}^{b}\] f(x) dx = \[\int_{a}^{c}\] f(x) dx + \[\int_{c}^{b}\] f(x) dx
5. \[\int_{0}^{a}\] f(x) dx = \[\int_{0}^{a}\] f(a - x) dx
Solved Example
Evaluate the given below integral?
Solution
Using integration by substitution
∫ sin(1 - x)(2 - cos(1 - x))
u = 2 - cos(1 - x) du = -sin(1 - x)dx ⇒sin(1 - x)dx = -du
∫sin(1 - x)(2 - cos(1 - x))
= - ⅕ (2 - cos(1 - x))
= -⅕(2 - cos(1 - x))
Fun Facts:
You can easily check the answer you got after integrating a function.
Differentiate the integrated function, if you get your question again it means you are right.
The symbol of integration ‘∫ ’ is a large “S” which stands for summa.
Summa is Latin for a sum. This was first used by Gottfried Wilhelm Leibniz.
FAQs on Integration of Trigonometric Functions
1. What types of questions on integration of trigonometric functions are considered important for CBSE Class 12 board exams?
Important questions generally focus on using standard integration techniques for sine, cosine, tangent, cotangent, secant and cosecant, as well as application-based integrals. You may encounter:
- Problems involving substitution and use of trigonometric identities
- Questions that ask for stepwise calculation with the correct constant of integration
- Definite integrals with given limits
- Application questions in physics or geometry using trigonometric integrals
2. Why is it essential to use the correct integration technique for trigonometric integrals in board exams?
Choosing the right integration technique, such as substitution, trigonometric identities, or integration by parts, is crucial because it simplifies the problem and leads to the correct answer efficiently. Incorrect technique can result in complex expressions and loss of marks as per the CBSE 2025–26 marking guidelines.
3. What are the most frequent mistakes students make in the Integration of Trigonometric Functions chapter during board exams?
Common errors include:
- Forgetting the constant of integration in indefinite integrals
- Incorrectly applying trigonometric identities
- Errors in sign (positive/negative) during calculation
- Mistakes when substituting or changing limits in definite integration
4. How can mastering integration of trigonometric functions help in higher studies or competitive exams?
Building a strong foundation in integration of trigonometric functions is essential for advanced mathematics topics such as differential equations, Fourier analysis, and solving physics problems on waves and oscillations. Confidence in these integrals is also crucial for exams like JEE, NEET, and university entrance tests.
5. What is the significance of the constant of integration ‘c’ in indefinite trigonometric integrals in CBSE board exams?
The constant of integration ‘c’ represents all possible values lost during differentiation. Its absence in your answer for indefinite integrals results in incomplete solutions and loss of marks in CBSE 2025–26 board exams. It is not needed in definite integrals because the limits provide a unique answer.
6. In what ways can integration of trigonometric functions be applied to real-world problems asked in board exams?
Trigonometric integrals commonly appear in real-life contexts such as:
- Finding the area under periodic curves
- Solving problems involving motion, waves, or oscillations
- Calculating physical quantities in electrical or mechanical engineering
Understanding these applications can help in scoring higher in application-based questions.
7. What exam strategy should students follow for 5-mark questions on integration of trigonometric functions in the CBSE Class 12 Maths paper?
For high-value questions:
- Write each step logically and clearly
- Highlight which integration method is being used
- Double-check for sign errors and inclusion of the constant of integration (if indefinite)
- State the final answer with proper justification
This structured approach meets the CBSE 2025–26 marking scheme for maximum marks.
8. How do you decide between substitution and trigonometric identities when integrating a complex trigonometric function?
First, analyze the form of the integrand:
- If the integrand matches a standard form after substitution, use that method
- When the integral involves product or quotient of sine and cosine, applying a suitable identity may simplify the expression
- Practice enables quick recognition of the most efficient approach during exams
9. Why do some trigonometric integrals only have one suitable method of solution?
Certain integrals, particularly those involving radicals such as √(a² – x²) or logarithmic forms, can only be solved efficiently and correctly using a specific substitution, such as x = a sin θ. Alternative methods either fail or produce more complex results, making these integrals best suited to a single approach.
10. How does the marking scheme for CBSE 2025–26 reward logical steps and justification in trigonometric integrals?
The CBSE marking scheme allocates marks for outlining the correct method, each logical step, accurate calculations, and properly presenting the answer, including the constant of integration where required. Missing any step or presenting an incomplete answer may reduce your score in the integration of trigonometric functions section.
11. What if you apply the wrong trigonometric identity in an exam question on integration?
Using an incorrect identity may lead to unsolvable or incorrect integrals, resulting in loss of marks. Reviewing identities and practicing application as per board exam expectations can help you avoid this conceptual pitfall.
12. How can you ensure that your answer to a definite integral involving trigonometric functions is complete and accurate in board exams?
For definite integrals:
- Always update the integration limits if you change variables
- Show all calculations clearly
- Remember the constant of integration is not needed for definite integrals
- Review the answer to ensure all steps are logically justified





