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Area of an Octagon Explained with Formula and Step by Step Solutions

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What Is the Formula for the Area of an Octagon with Solved Examples

Any 2-dimensional shape with more than 2 line segments is called a polygon. Some known polygon examples include square, triangle, rectangle, pentagon, etc. Likewise, polygons with 8 sides in a 2-dimensional plane are known as an octagon. These shapes can again be divided into categories depending on their side and angle measurements. In this section, students will learn about the different types of octagons and how that affects their properties and calculations, including the area of an octagon.

 

Read on to get acquainted with the basics before heading on with the formulae.

 

Types of Octagons

Octagons can be divided into 2 types, based on their side lengths.

 

  1. Regular Octagon:

An octagon with equal-length sides and all the same value angles is called a regular octagon.

 

  1. Irregular Octagon:

If octagon sides and angles are unequal, it is called an irregular octagon.

 

Properties of a Regular Octagon

Following are the features of a regular octagon.

  • It comprises 8 sides and 8 angles.

  • The measurement of each side is equal, as is the case with its angles.

  • A regular octagon comprises a total of 20 diagonals.

  • Each interior angle measures 135°, summing up to 1080° degrees.

  • Each of a regular octagon’s exterior angles measures 45°, giving a total sum of 360°.

Based on the above characteristics, students can derive many other properties of an octagon, which they will need to solve the varied numerical that they will encounter under this topic. Read on to know how to derive some of these like area, perimeter, and diagonal formulas for an octagon.

 

Area of a Regular Octagon

The most widely used formula to calculate the area of a regular octagon is given as:

 

A = 2a2 (1 + √2), where a represents the given octagon’s each side length.

 

To derive this equation, consider the given pentagon. Drawing all its diagonals has divided it into 8 isosceles triangles with the center as their common apex.

 

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Calculating the area of one of these similar triangles, and multiplying it by 8 will give you the given octagon’s area. To calculate a triangle’s area, draw a perpendicular line OP joining the apex to base AB’s bisectional point, as shown in the figure below. This is an apothem of an octagon, which can be calculated by dividing any of the longest diagonals by 2.

 

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Here, AB = side of given octagon = a

 

Therefore AP = PB = a/2

 

Now, angle OPB = angle OPA = 90° 

 

And angle OAP = 135/2°, and angle AOP = θ = 45/2°, by construction.

 

To determine OD’s length, solve trigonometric expressions for θ.

 

2 sin² θ = 1 - cos 2θ – (i)

 

2 cos² θ = 1 + cos 2θ – (ii) 

 

Divide (i) by (ii),

 

tan2 θ = (1 - cos 2θ) / (1 + cos 2θ) – (iii)

 

Put the value of θ in equation (iii),

 

tan2 (45/2) = (1 - cos 45) / (1 + cos 45)

 

Substitute the value of cos 45 as 1/√2,

 

tan2 (45/2) = (1 – 1/√2) / (1 + 1/√2) = (√2 – 1) / (√2 + 1) = (√2 – 1)2/1

 

tan (45/2) = √2 - 1

 

Since angle AOP = 45/2°, tan (45/2) = AP/OP

 

i.e., AP/OP= √2 - 1

 

or, OP = AP / (√2 – 1) = (a/2) / (√2 – 1) = (a/2) (1+√2) 

 

Therefore, area of ∆ OAB = (1/2) x AB x OP = (1/2) x a x (a/2) (1+√2) = (a2/4) (1+√2)

 

As discussed earlier, area of regular octagon= 8 x area of ∆ OAB = 8 x (a2/4) (1+√2)

 

Hence, proved the area of an octagon = 2a2 (1 + √2).

 

Area of an Irregular Octagon

The above formulae to calculate the area of an octagon were for the condition that every side and angle are equal. For irregular shapes like the one given below, the previous formulae are obsolete.

 

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In this scenario, to calculate the area of an octagon formula, you need to visualize a given octagon divided into different polygons, whose necessary measurements are known or can be derived from given information. Now, calculate each of these polygons’ area with their known area formulae. Lastly, add calculated areas of these polygons to find the area of the octagon.

 

The formula to find the area of some common polygons, besides triangle are given below.

 

  • Area of square = s2, where s represents each side’s length.

  • Area of rectangle = l x b, where l stands for length and b represents width.

  • Area of parallelogram = b x h, where b is its base length, and h is its height.

 

The perimeter of an Octagon

The total distance covered by an octagon’s periphery is called its perimeter. In other words, it is the length of its boundary. Therefore calculating the perimeter of the octagon formula is nothing but a sum of the measurement of all its sides. Therefore, it can be represented as:

 

The perimeter of octagon = 8a, where a is the given polygon’s each side length.

 

Length of a Diagonal of an Octagon

The diagonal of an octagon is a line drawn to join any pair of its opposite vertices. A regular octagon comprises 4 equal diagonals, each of which divides it into two similar pentagons. The formula to calculate their length is given as:

 

L = a √( 4 + 2√2), where a is the length of each side of the octagon.

 

The above formula can be derived as follows.

 

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In ∆ AED in given diagram, AE2 + DE2 = AD2, (Pythagoras’ theorem for right-angled triangle)

 

i.e., b2 + b2 = a2

 

⇒ b = a / √2 – (iv)

 

Now, AB = 2b + a = a√2 {substituting b’s value form (iv)}, and BC = a.

 

In ∆ABC, AC2 = AB2 +BC2

 

Therefore, length of diagonal AC = a √(4 + 2√2).

 

Now, you can implement diagonal length calculated by this formula to find the area of an octagon. 

 

The Area of the octagon for class 8 is an important concept to help students develop a clear foundation of geometry for efficient numerical solving as well as higher studies. A thorough study of prescribed textbooks undoubtedly comes first for exam preparation. For a more detailed understanding of this topic along with illustrations and exercises on different types of problem sums, refer to online tutoring sites like Vedantu. Download the app to avail of live expert guidance.


Properties of an Octagon

The area of an octagon is studied much earlier in classes, however, it is mainly introduced in the eighth grade in chapter 3 called understanding quadrilaterals. This chapter is mainly concerned with the various types of polygons and their classification. For example, some of the polygons are triangle, quadrilateral, Pentagon, hexagon, heptagon, octagon, nonagon, decagon. This chapter also explains in-depth diagonals, convex and concave polygons, regular and irregular polygons, angles some properties, some of the measures of the exterior angles of a polygon. After studying these figures in-depth this chapter further explains the kinds of quadrilaterals like trapezium, kite, parallelogram, elements of a parallelogram, angles of a parallelogram, diagonals of a parallelogram, this chapter goes on to further explain some special parallelogram such as rhombus, rectangle, a square.


An octagon is a type of polygon, a polygon can be defined as a figure having a two-dimensional closed figure which is made of straight line segments having three or more sides. An octagon is a figure having eight sides. The word octagon originated from greek octagonal, which means “eight angles”. There are two types of octagons, regular and irregular octagons. A regular octagon mainly consists of eight sides having an equal length and equal internal angles that is 135° and internal angles being 45°. And a regular octagon has eight different sides, these types of figures are not symmetric and they do not have a center. There are many examples of an octagon that can be seen in our day-to-day life for example the stop sign used in many places is usually in the shape of an octagon.


Get an Edge with Vedantu

The article mainly discusses in detail the types of octagons that are regular and irregular octagon, properties of a regular octagon, area of a regular octagon, area of an irregular octagon, perimeter of an octagon, length of a diagonal of an octagon. These are the basic concepts that are all mandatory for students to understand and get a good hold over them as it is only after getting The basics cleared that a student can excel further in studies. The objective of this article is to make students efficient in solving the area and perimeter of an octagon.


Finding the area for a long time can be a difficult task for some students and in order to make the learning process easier Vedantu’s expert mathematics teachers who have years of experience have done extensive research on the topic area of the octagon and they have explained this concept in an extremely simplified manner so that students who find it difficult can also get a good grasp over the calculations regarding an octagon.

FAQs on Area of an Octagon Explained with Formula and Step by Step Solutions

1. What is the formula for the area of a regular octagon?

The formula for the area of a regular octagon is A = 2(1 + √2)s², where s is the side length.

  • This formula works only for a regular octagon (all sides and angles equal).
  • √2 is approximately 1.414.
  • You can also express it as A ≈ 4.828s² after simplification.

2. How do you calculate the area of a regular octagon step by step?

To calculate the area of a regular octagon, use the formula A = 2(1 + √2)s².

  • Step 1: Measure the side length (s).
  • Step 2: Square the side length (s²).
  • Step 3: Multiply by 2(1 + √2).
Example: If s = 5 cm, then A = 2(1 + √2)(25) ≈ 2(2.414)(25) ≈ 120.7 cm².

3. What is the area of an octagon with side length 10 units?

The area of a regular octagon with side length 10 units is approximately 482.8 square units.

  • Use the formula: A = 2(1 + √2)s²
  • Substitute s = 10
  • A = 2(1 + √2)(100)
  • A ≈ 2(2.414)(100) ≈ 482.8

4. How do you find the area of an octagon using the apothem?

The area of a regular octagon using the apothem is A = ½ × perimeter × apothem.

  • First, calculate the perimeter (8 × side length).
  • Then multiply the perimeter by the apothem.
  • Finally, multiply by ½.
This formula works for all regular polygons, including a regular octagon.

5. Can you find the area of an irregular octagon?

Yes, the area of an irregular octagon can be found by dividing it into simpler shapes like triangles and rectangles.

  • Break the octagon into known shapes.
  • Find the area of each part separately.
  • Add all areas together.
There is no single formula like A = 2(1 + √2)s² for an irregular octagon.

6. Why is the formula for the area of a regular octagon 2(1 + √2)s²?

The formula 2(1 + √2)s² comes from dividing a regular octagon into triangles or combining it from a square and four right triangles.

  • A regular octagon can be split into 8 congruent isosceles triangles.
  • Using trigonometry or geometric construction leads to the simplified expression.
  • The constant (1 + √2) arises from geometric relationships in a 45° triangle.

7. What is the difference between the area formula of a regular and irregular octagon?

A regular octagon has a fixed formula A = 2(1 + √2)s², while an irregular octagon does not have a single standard formula.

  • Regular octagon: All sides and angles equal, use direct formula.
  • Irregular octagon: Sides and angles vary, divide into smaller shapes.
This is a key difference in solving geometry problems.

8. How is the area of an octagon related to its perimeter?

The area of a regular octagon is related to its perimeter through the formula A = ½ × perimeter × apothem.

  • Perimeter = 8s
  • Multiply by the apothem.
  • Then multiply by ½.
This relationship applies to all regular polygons, not just octagons.

9. What is the area of an octagon inscribed in a square?

The area of an octagon inscribed in a square can be found by subtracting the four corner triangles from the square’s area.

  • Find the area of the square.
  • Find the area of one corner triangle.
  • Multiply the triangle’s area by 4.
  • Subtract from the square’s area.
This method is commonly used in geometric construction problems.

10. What are common mistakes when finding the area of an octagon?

A common mistake when finding the area of an octagon is using the regular formula for an irregular shape.

  • Confusing perimeter with area.
  • Forgetting to square the side length in A = 2(1 + √2)s².
  • Using the wrong units (area must be in square units).
  • Not checking if the octagon is regular before applying the formula.